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6x^2+113x+308=0
a = 6; b = 113; c = +308;
Δ = b2-4ac
Δ = 1132-4·6·308
Δ = 5377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(113)-\sqrt{5377}}{2*6}=\frac{-113-\sqrt{5377}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(113)+\sqrt{5377}}{2*6}=\frac{-113+\sqrt{5377}}{12} $
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